Why JavaScript's sort() Fails with Numbers and How to Fix It
JavaScript's built-in sort() method sorts elements as strings by default, which produces incorrect results when applied to numbers. For example, '25' is treated as greater than '100' because the character '2' ranks higher than '1' in string comparison. Developers can fix this by passing a compare function that subtracts one number from another, returning a negative, zero, or positive value. A negative result places the first value before the second, a positive result reverses that order, and zero leaves them unchanged. This approach allows accurate ascending or descending numeric sorting with minimal code.
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