LeetCode 31: How to Find the Next Permutation in O(n) Time
LeetCode problem 31 asks developers to rearrange an array into its next lexicographically greater permutation. The approach involves scanning from right to left to find the first element smaller than its right neighbor, then finding the first element greater than it to swap. After the swap, the suffix following the swapped index is reversed to produce the smallest possible arrangement. A corner case is handled when the array is in fully descending order, in which case the entire array is simply reversed. The solution runs in O(n) time with O(1) auxiliary space.
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